计算（x+2-5/x-2）除以3-x/2x-4

[(x+2)-5/(x-2)]÷(3-x)/(2x-4)
=[(x+2)-5/(x-2)]*2(x-2)/(3-x)
=2[(x+2)(x-2)-5]/(3-x)
=2(x^2-4-5)/(3-x)
=-2(x^2-9)/(x-3)
=-2(x+3)(x-3)/(x-3)
=-2(x+3)
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