问题描述: 1959+3910−5.221959−62750+5.22÷(1993×0.41995×0.5+1.61995) 1个回答 分类:数学 2014-11-04 问题解答: 我来补答 1959+3910−5.221959−62750+5.22÷(1993×0.41995×0.5+1.61995),=1959−1.321959−1.32÷1993×0.4+0.81995×0.5,=1÷0.4×(1993+2)1995×0.5,=1÷45,=54. 再问: /就是横杠 展开全文阅读