问题描述: 已知x/y=1/2,求2x/(x²-2xy+y² )* (x²-y²/x+y)+2y/x-y 1个回答 分类:数学 2014-12-04 问题解答: 我来补答 [2x/(x²-2xy+y² )]* [(x²-y²)/(x+y)]+2y/(x-y) 【电脑上录入表达式,尽可能多用括号,否则多歧义】=[2x/(x-y)²]* [(x+y)(x-y)/(x+y)]+2y/(x-y)=2x/(x-y)+2y/(x-y)=2(x+y)/(x-y) 【分子分母都除以y】=2(x/y+1)/(x/y-1) =2(1/2+1)/(1/2-1)=-6 展开全文阅读