如图,ab为圆o的弦,直径cd⊥ab于e,弦af交直径cd于点g,oh⊥af于点h,若ab=6cm,ce=1cm,oh=

连解AO,BO,OF
∵AO=BO=FO,CD⊥AB,OH⊥AF
∴AE=BE,AH,HF
∴AE²=AO²-OE²
(AB/2)²=AO²-(CO-CE)²
9=R²-(R-1)²
R=5
AH²=AO²-HO²
(AF/2)²=AO²-HO²
AF=4√6