计算 1/2+3/4+7/8+15/16+31/32+63/64+127/128+255/256

问题描述:

计算 1/2+3/4+7/8+15/16+31/32+63/64+127/128+255/256
1个回答 分类:数学 2014-10-28

问题解答:

我来补答
1/2+3/4+7/8+15/16+31/32+63/64+127/128+255/256
=(1-1/2)+(1-1/4)+(1-1/8)+(1-1/16)+(1-1/32)+(1-1/64)+(1-1/128)+(1-1/256)
=1*8-(1/2+1/4+1/8+1/16+1/32+1/64+1/128+1/256)
=8-(1/2+1/4+1/8+1/16+1/32+1/64+1/128+1/256+1/256)+1/256
=8-(1/2+1/4+1/8+1/16+1/32+1/64+1/128+1/128)+1/256
=8-(1/2+1/4+1/8+1/16+1/32+1/64+1/64)+1/256
=8-(1/2+1/4+1/8+1/16+1/32+1/32)+1/256
=8-(1/2+1/4+1/8+1/16+1/16)+1/256
=8-(1/2+1/4+1/8+1/8)+1/256
=8-(1/2+1/4+1/4)+1/256
=8-(1/2+1/2)+1/256
=8-1+1/256
=7+1/256
所以,结果为:
七又二百五十六分之一
轻松一下!
 
 
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