问题描述: 复数的运算 计算(2+5i)÷3i+(√3+i)(√3-i)求解答步骤 1个回答 分类:数学 2014-10-25 问题解答: 我来补答 (2+5i)/3i+(√3+i)(√3-i)= -(2/3)i +5/3 +(3+1)=17/3-(2/3)i 再问: = -(2/3)i +5/3 +(3+1) =17/3-(2/3)i答案没错,我就是想知道这两步是怎么算的 再答: (√3+i)(√3-i) =(√3)^2-(i)^2 = 3+1=4 (2+5i)/3i =2/(3i) + 5i/(3i) = 2i/(3i^2) + 5/3 = -(2/3) i +5/3 展开全文阅读