问题描述: ∫(x+1)/(x^2-2x+5)dx 1个回答 分类:数学 2014-10-15 问题解答: 我来补答 ∫(x+1)/(x^2-2x+5)dx=1/2*∫(2x-2)/(x^2-2x+5)dx+∫2/(x^2-2x+5)dx=1/2*∫[1/(x^2-2x+5)]d(x^2-2x+5)+2∫1/[(x-1)^2+2^2])d(x-1)=1/2*ln(x^2-2x+5)+arctan[(x-1)/2]+C 展开全文阅读