问题描述： 1/x²+x+1/x²+3x+2+1/x²+5x+6+1/x²+7x+12,分式方程, 1个回答 分类：数学 2014-10-17 问题解答： 我来补答 原式=1/x(x+1)+1/(x+1)(x+2)+1/(x+2)(x+3)+1/(x+3)(x+4)=1/x-1/(x+1)+1/(x+1)-1/(x+2)+1/(x+2)-1/(x+3)+1/(x+3)-1/(x+4)=1/x-1/(x+4)=4/(x²+4x) 展开全文阅读
