求1/x(x+1)+2/(x+1)(x+3)+3/(x+3)(x+6)的值

问题描述:

求1/x(x+1)+2/(x+1)(x+3)+3/(x+3)(x+6)的值
1个回答 分类:数学 2014-11-06

问题解答:

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1/x(x+1)+2/(x+1)(x+3)+3/(x+3)(x+6)
=1/x-1/(x+1)+1/(x+1)-1/(x+3)+1/(x+3)-1/(x+6)
= 1/x-1/(x+6)
=(x+6-x)/[x(x+6)]
=6/[x(x+6)]
 
 
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