问题描述: (a^2-b^2)/ab-(ab-b^2)/(ab-a^2)x/(x^2-y^2)-y/(x^2+2xy+y^2) 1个回答 分类:数学 2014-10-27 问题解答: 我来补答 (a^2-b^2)/ab-(ab-b^2)/(ab-a^2)=(a^2-b^2)/ab-b(a-b)/a(b-a)=(a^2-b^2)/ab-(-b)/a=(a^2-b^2)/ab+b/a=(a^2-b^2)/ab+b^2/ab=(a^2-b^2+b^2)/ab=a^2/ab=a/bx/(x^2-y^2)-y/(x^2+2xy+y^2)=x/[(x+y)(x-y)]-y/(x+y)^2=x(x+y)/[(x+y)^2(x-y)]-y(x-y)/[(x+y)^2(x-y)]=(x^2+xy-yx+y^2)/[(x+y)^2(x-y)]=(x^2+y^2)/[(x+y)^2(x-y)]这个不会看不懂吧 展开全文阅读