在复数范围内分解因式（1） 27^3+8 （2）4x^4+3x^2-1

(1)
27x^3+8
=(3x)^3+2^3
=(3x+2)*(9x^2-6x+4)
=(3x+2)*9*[x-(1+√3i)/3][x-(1-√3i)/3]
=(3x+2)*[3x-(1+√3i)][3x-(1-√3i)]
(2)
4x^4+3x^2-1
=(4x^2-1)(x^2+1)
=(2x-1)(2x+1)(x-i)(x+i)