问题描述： 因式分解x^4+y^4+z^4-2x^2y^2-2y^2z^2-2z^2x^2 1个回答 分类：数学 2014-11-24 问题解答： 我来补答 x^4+y^4+z^4-2x^2y^2-2y^2z^2-2x^2z^2= x^4+2x^2y^2+y^4-2z^2(x^2+y^2)+z^4-4x^2y^2= (x^2+y^2)^2-2z^2(x^2+y^2)+z^4-4x^2y^2= (x^2+y^2-z^2)^2-4x^2y^2= (x^2+y^2-z^2+2xy)(x^2+y^2-z^2-2xy)= [(x+y)^2-z^2][(x-y)^2-z^2]= (x+y+z)(x+y-z)(x-y+z)(x-y-z) 展开全文阅读
