概率计算问题C(2n+7,n+8）*0.5^2n+7中文描述如下：C2n+7,n+8乘以0.5的2n+7次方,当n为几时

设函数y(n)=C(2n+7,n+8）*0.5^2n+7
则y(n+1)=C(2n+9,n+9）*0.5^2n+9
y(n+1)/y(n)=(2n+9)(2n+8)*0.25/n(n+9)
要使y(n+1)/y(n)≥1
则(2n+9)(2n+8)*0.25/n(n+9)≥1
(2n+9)(2n+8)≥4n(n+9)
即n≤36
于是当n=36或37时,函数取得最大值