总共三道3(x+2)^2=x^2-43(x-2)^2=2x^2-4x9(x+1)^2=4(1-2x)^2

问题描述:

总共三道
3(x+2)^2=x^2-4
3(x-2)^2=2x^2-4x
9(x+1)^2=4(1-2x)^2
1个回答 分类:数学 2014-11-03

问题解答:

我来补答
3(x+2)^2=x^2-4
3(x+2)^2-(x+2)(x-2)=0
(x+2)[3(x+2)-(x-2)]=0
(x+2)(2x+8)=0
x=-2,x=-4
3(x-2)^2=2x^2-4x
3(x-2)^2-2x(x-2)=0
[3(x-2)-2x](x-2)=0
(x-6)(x-2)=0
x=6,x=2
9(x+1)^2=4(1-2x)^2
[3(x+1)]^2-[2(1-2x)]^2=0
(3x+3)^2-(2-4x)^2=0
(3x+3+2-4x)(3x+3-2+4x)=0
-(x-5)(7x+1)=0
x=5,x=-1/7
 
 
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