已知：x-3/2的绝对值+（y+2）平方=0,求x-2(1/4x-1/3y的平方）+（-3/2x+1/3y的平方）的值

x-3/2的绝对值+（y+2）平方=0
x-3/2=0 y+2=0
x=3/2 y=-2
x-2(1/4x-1/3y的平方）+（-3/2x+1/3y的平方）
=x-1/2x+2/3y^2-3/2x+1/3y^2
=-x+y^2
=-3/2+(-2)^2
=-3/2+4
=5/2