解方程x²+x-6分之5x+x²-x-12分之2x-5=x²-6x+8分之7x-10

5x/(x²+x-6)+(2x-5)/(x²-x-12)=(7x-10)/(x²-6x+8)
5x/(x-2)(x+3)+(2x-5)/(x+3)(x-4)=(7x-10)/(x-2)(x-4)
5x(x-4)+(2x-5)(x-2)=(7x-10)(x+3)
5x^2-20x+(2x^2-9x+10)=7x^2+11x-30
7x^2-29x+10=7x^2+11x-30
40x=40
x=1
经检验,x=1是方程的解