为什麽log(a)(x+b/x-b)=y可化得x=b(a的y次方+1)/a的y次方-1

aˇy=(x+b)/(x-b)
aˇy * (x-b)=x+b
aˇy * x - aˇy * b = x+b
aˇy * x - x = b+ aˇy * b
x * (aˇy - 1)= b * (1 + aˇy)
x=b * (1 + aˇy)/(aˇy - 1)