问题描述:
反应4 NH3(g)+5 O2(g)=4 NO(g)+6 H2O(g)在10L的密闭容器中进行,0.5min后,水蒸气的物质的量增加了0.45摩,则此反应的速率V(X)可表示为()
A.V(NH3)=0.010mol/L/s
B.V(O2)=0.0010mol/L/s
C.V(NO)=0.0010mol/L/s
D.V(H2O)=0.045mol/L/s
A.V(NH3)=0.010mol/L/s
B.V(O2)=0.0010mol/L/s
C.V(NO)=0.0010mol/L/s
D.V(H2O)=0.045mol/L/s
问题解答:
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