问题描述：
为什么我用热辐射定理算出来地球至少60摄氏度?
按照Stephen-Boltzmann law& Inverse-square law
(Asun εsun Tsun^4 )*(2π rearth^2) /(4π AU^2)= Aearth εearth Tearth^4
得[(Asun εsun)/(8π AU^2 εearth)]^.25 Tsun= Tearth=332K=60℃
其中AU= 1.49598 ×1011 m
Asun=6.0877×1018 m2
εsun =1
Tsun=5,778 K
按照Stephen-Boltzmann law& Inverse-square law
(Asun εsun Tsun^4 )*(2π rearth^2) /(4π AU^2)= Aearth εearth Tearth^4
得[(Asun εsun)/(8π AU^2 εearth)]^.25 Tsun= Tearth=332K=60℃
其中AU= 1.49598 ×1011 m
Asun=6.0877×1018 m2
εsun =1
Tsun=5,778 K
问题解答：
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