如图,在平行四边形ABCD中,E为BC边上一点,且AB=AE.若AE平分∠DAB,∠EAC=25°,求∠AED的度数.

1.∠EAD=∠BEA=∠BAE
BA=BE
AB=AE
△ABE是正三角形.
AE=CD
△AEC≌△DCE
∠AED=∠ACD=∠BAC=85°.
2.EF‖BD
CE/BE=CF/DF
BE/BC=DF/CD
SABE/SABCD=BE/2BC
SADF/SABCD=DF/2CD
SABE/SABCD=SADF/SABCD
SABE=SADF.