关于平衡常数equilibrium constant (Ka)的问题

问题描述:

关于平衡常数equilibrium constant (Ka)的问题
俺做题目的时候搞了半天没搞懂 摆脱那位大大帮忙解答下
HF + H2O H3O+ + F- Ka = 7.2 x 10-4
HS- + H2O H3O+ + S2- Ka = 1.3 x 10-13
CH3COOH + H2O H3O+ + CH3COO- Ka = 1.8 x 10-5
(i) Which is the strongest acid?
(ii) Which is the weakest acid?
(iii)What is the conjugate base of the acid HF?
(iv) Which acid has the weakest conjugate base?
(v) Which acid has the strongest conjugate base?
1个回答 分类:综合 2014-11-14

问题解答:

我来补答
你在国外读书吧?:)
(i)HF is the strongest acid since it has the largest value of Ka.HF酸性最强,因为它平衡常数最大.
(ii)HS- is the weakest acid since it has the smallest value of Ka.HS- 酸性最弱,因为它平衡常数最小.
(iii)F- is the conjugate base of HF.F-是HF的共轭碱.
(iv)HF(the strongest acid) has the weakest conjugate base.HF是最强的酸,它有最弱的共轭碱.
(v)HS- (the weakest acid) has the strongest conjugate base.HS-是最弱酸,它有最强的共轭碱.
以下是解答这五道题的思路依据:
(i)(ii)The lager the value of Ka,the stronger the acid.平衡常数越大,酸性越强.
(iii)Every acid has a conjugate base,formed by removing a proton from the acid.每种酸都有一个与之对应的共轭碱,此共轭碱的化学式是将原来那种酸的化学式去掉一个质子(氢离子).
(iv)(v)The stronger an acid,the weaker is its conjugate base; the stronger a base,the weaker is its conjugate acid.一种酸的酸性越强,它的共轭碱就越弱;一种碱的碱性越强,它的共轭酸就越弱.
 
 
展开全文阅读
剩余:2000
上一页:算数过程
下一页:enjoy的反义词