已知a>b>0,a+b=6又根号ab,则根号a加根号b分之根号a减根号b的值为

(√a-√b)^2/(√a+√b)^2
=(a+b-2√ab)/(a+b+2√ab)
=(6√ab-2√ab)/(6√ab+2√ab)
=4√ab/8√ab=1/2,
所以(√a-√b)/(√a+√b)=√2/2.