a-1分之2+a²-1分之a²-4a+4÷a+1分之a-1,其中a等于1加根号2

原式=2/(a-1)+(a-2)²/[(a+1)(a-1)]×(a+1)/(a-1)
=2/(a-1)+(a-2)²/(a-1)²
=2(a-1)/(a-1)²+(a-2)²/(a-1)²
=(2a-2+a²-4a+4)/(a-1)²
=(a²-2a+2)/(a-1)²
=[(a-1)²+1]/(a-1)²
=1+1/(a-1)²
∵a=1+√2
∴原式=1+1/(1+√2-1)²
=1+1/2
=3/2
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