问题描述: 已知x^2加根号2y等于根号3,y的平方加根号2x等于根号3,x≠y,求xy,x+y的值 1个回答 分类:数学 2014-10-15 问题解答: 我来补答 x²+√2y=√3.1y²+√2x=√3.21-2得:x²+√2y-(y²+√2x)=0x²-y²+√2(y-x)=0(x+y)(x-y)-√2(x-y)=0(x-y)(x+y-√2)=0∵x≠y,∴x-y≠0∴x+y-√2=0,x+y=√2又1+2式得:x²+√2y+(y²+√2x)=2√3x²+y²+√2(x+y)=2√3(x+y)²-2xy+√2(x+y)=2√3∵x+y=√2∴(√2)²-2xy+√2*√2=2√3∴xy=2-√3 展开全文阅读