问题描述: 设f(x)在【0,1】上连续.证明∫(π/2~0)f(cosx)dx=∫(π/2~0)f(sinx)dx 1个回答 分类:数学 2014-10-19 问题解答: 我来补答 令 y=π/2-x,则x=π/2-y∫(π/2~0)f(cosx)dx=∫(0~π/2) f(cos(π/2-y))d(π/2-y)=∫(0~π/2) -f(siny)dy=-∫(0~π/2) f(siny)dy=∫(π/2~0)f(siny)dy=∫(π/2~0)f(sinx)dx 展开全文阅读