(1)化简分式(x^2-1/x^2+2x+1)-(x+1/x-1)

问题描述:

(1)化简分式(x^2-1/x^2+2x+1)-(x+1/x-1)
(2)解方程(x-1/x)-(x/x-1)=5/2
(3)解不等式组2-x>0
( 5x+1/2)+1>=(2x-1/3)
1个回答 分类:数学 2014-12-04

问题解答:

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(1)化简分式(x^2-1/x^2+2x+1)-(x+1/x-1)
=(x+1)(x-1)/(x+1)^2-(x+1)/(x-1)
=(x-1)/(x+1)-(x+1)/(x-1)
=[(x-1)^2-(x+1)^2]/(x^2-1)
=-4x/(x^2-1)
(2)解方程(x-1/x)-(x/x-1)=5/2
(-2x+1)/x(x-1)=5/2
-4x+2=5x^2-5x
5x^2-x-2=0
(x-1/10)^2=41/100
x=(1±√41)/10
(3)解不等式组2-x>0
( 5x+1/2)+1>=(2x-1/3)
x=2x-1/3
x>=-11/18
-11/18≤x
 
 
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