有一道sat的试题麻烦解答一下 The 3rd term of a geometric seq

问题描述:

有一道sat的试题麻烦解答一下 The 3rd term of a geometric seq
uence is -3,and the 6th term is (八分之三.)what is the 4th term of the sequence?
1个回答 分类:综合 2014-10-02

问题解答:

我来补答
geometric sequence是等比级数 第二个数字是第一个乘以某个数字a,ar,ar^2 (表示r的2次方),ar^3,ar^4,ar^5 ...
第三个是ar^2 = -3;
第六个是ar^5 = 3/8;
那么第六个除以第三个 就是r^3 = -1/8
r就是-1/2
所以第4个sequence就是ar^2 * r = (-3) * (-1/2) = 3/2 或者1.5
 
 
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