设f(x)是R上的函数,且满足f(0)=1,且对x,y∈R都有f(x-y)=f(x)-y(2x-y+1),则f(x)的表

令y=x,则f(x-y)=f(x)-y(2x-y+1),
f(x-x)=f(x)-x(2x-x+1)
f(0)=f(x)-x^2-x
f(X)=X^2+X+1