问题描述: 极坐标方程ρ=2sin(θ-π /4) 表示的曲线是? 1个回答 分类:数学 2014-10-17 问题解答: 我来补答 ρ=2sin(θ-π/4)ρ^2=2ρsin(θ-π/4)x^2 + y^2 = 2ρsinθcosπ/4-2ρcosθsinπ/4x^2 + y^2 = √2ρsinθ - √2ρcosθx^2 + y^2= √2y - √2xx^2 + √2x + y^2 - √2y =0x^2 + √2x + 1/2 + y^2 - √2y +1/2 =1(x+1/√2)^2 + (y-1/√2)^2 = 1即圆心(-1/√2,1/√2)半径为1的圆√2:2开平方 π 圆周率应用公式:ρ^2 = x^2 + y^2x=ρcosθ y=ρsinθ 展开全文阅读