Lg5*Lg8000+(Lg2√3^2+Lg0.06-Lg6=?

问题描述:

Lg5*Lg8000+(Lg2√3^2+Lg0.06-Lg6=?
1个回答 分类:数学 2014-11-06

问题解答:

我来补答
lg5*lg8000+(lg2^根号3)^2+lg0.06-lg6
=lg5*(lg8+lg1000)+(√3*lg2)^2+lg(6/100)-lg6
=lg5*(3lg2+3)+3*(lg2)^2+lg[(6/100)/6]
=3lg2*lg5+3lg5+3(lg2)^2+lg(1/100)
=3lg2(lg2+lg5)+3lg5+lg10^(-2)
=3lg2*lg10+3*lg5-2
=3lg2+3lg5-2
=3(lg2+lg5)-2
=3*1-2
=1
 
 
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