(x+2/x的平方+2x - x-1/x的平方-4x+4) / x-4/x × (2-x)的平方

原式=[(x+2)/x(x+2)-(x-1)/(x-2)²]÷[(x²-4)/x]×(x-2)²
=[x-(x-1)/(x-2)²]×[x/(x+2)(x-2)]×(x-2)²
=[x-(x-1)/(x-2)²]×[x(x-2)/(x+2)]
=x×[x(x-2)/(x+2)]-(x-1)/(x-2)²×[x(x-2)/(x+2)]
=x²(x-2)/(x+2)-x(x-1)/(x-2)(x+2)
你写错了吧