问题描述:
c语言:编程统计数组a中的正数,0,负数的个数,并输出统计结果?
(1)#include "stdio.h"
int main()
{
int s[40],i=0,j,num=0,a=0,b=0,c=0;
for (i=0;s[i]!='\n';i++ )
{scanf("%d",&s[i]);
num++;
}
for(j=0;j0) a++;
else if (s[j]==0) b++;
else c++;
}
printf("数组a中正数有%d个,0有%d个,负数%d个",a,b,c);
}
(2)
#include "stdio.h"
int main()
{
int s[40],i=0,j,num=0,a=0,b=0,c=0;
while (s[i]!='\n')
{
num++;
i++;
}
for (i=0;i
(1)#include "stdio.h"
int main()
{
int s[40],i=0,j,num=0,a=0,b=0,c=0;
for (i=0;s[i]!='\n';i++ )
{scanf("%d",&s[i]);
num++;
}
for(j=0;j0) a++;
else if (s[j]==0) b++;
else c++;
}
printf("数组a中正数有%d个,0有%d个,负数%d个",a,b,c);
}
(2)
#include "stdio.h"
int main()
{
int s[40],i=0,j,num=0,a=0,b=0,c=0;
while (s[i]!='\n')
{
num++;
i++;
}
for (i=0;i
问题解答:
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