问题描述:
已知函数f(x)=1/3x^3-x^2+ax(a为常数) (1)若f(x)在区间[-1,2]上单调递减,求a的取值
(2)若f(x)与直线y=-9相切:(i)求a的值;(ii)设f(x)在x1,x2(x1
(2)若f(x)与直线y=-9相切:(i)求a的值;(ii)设f(x)在x1,x2(x1
问题解答:
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