问题描述:
MATLAB程序问题
解一个方程组如下
syms x y z t a b c d m s;
f = x+z-a;
g = (2^(1/2)*m*x)/2 + (2^(1/2)*m*y)/2+(2^(1/2)*m*t)/2 - (2^(1/2)*m*z)/2-b;
h = m^2*(y- t)-m^2*c;
k = (2^(1/2)*m^3*(y-x+z+t))/2-m^2*d;
[x,y,z,t] = solve(f,g,h,k);
x = simplify(x),
y = simplify(y),
z = simplify(z),
t = simplify(t)
x =
(2^(1/2)*(b + d))/(4*m) - c/2
y =
a/2 + (2^(1/2)*(b - d))/(4*m)
z =
c/2 + (2^(1/2)*(b + d))/(4*m)
t =
a/2 - (2^(1/2)*(b - d))/(4*m)
将x,z带入f方程,明显不成立,运行给的这个答案把x,y 的值和z,t的对调了.求教原因?
解一个方程组如下
syms x y z t a b c d m s;
f = x+z-a;
g = (2^(1/2)*m*x)/2 + (2^(1/2)*m*y)/2+(2^(1/2)*m*t)/2 - (2^(1/2)*m*z)/2-b;
h = m^2*(y- t)-m^2*c;
k = (2^(1/2)*m^3*(y-x+z+t))/2-m^2*d;
[x,y,z,t] = solve(f,g,h,k);
x = simplify(x),
y = simplify(y),
z = simplify(z),
t = simplify(t)
x =
(2^(1/2)*(b + d))/(4*m) - c/2
y =
a/2 + (2^(1/2)*(b - d))/(4*m)
z =
c/2 + (2^(1/2)*(b + d))/(4*m)
t =
a/2 - (2^(1/2)*(b - d))/(4*m)
将x,z带入f方程,明显不成立,运行给的这个答案把x,y 的值和z,t的对调了.求教原因?
问题解答:
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