1+(3/2)-(5/6)+(7/12)-(9/20)+.+(19/90)-(21/110)=?

问题描述:

1+(3/2)-(5/6)+(7/12)-(9/20)+.+(19/90)-(21/110)=?
括号内是分数
还有几道
这是第6题
11题.12题.13题.15题

第六题会了
第11题回了
1个回答 分类:数学 2014-11-25

问题解答:

我来补答
1+(3/2)-(5/6)+(7/12)-(9/20)+.+(19/90)-(21/110)
=1+1+1/2-1/2-1/3+1/3+1/4-1/4-1/5+……+1/9+1/10-1/10-1/11
=2-1/11
=1又10/11
(7)1/3+1/15+1/35+1/63+1/99+……+1/9999
=1/2×(1-1/3+1/3-1/5+1/5-1/7+1/7-1/9+1/9-1/11+……+1/99-1/101)
=1/2×(1-1/101)
=1/2×100/101
=50/101
(8)2/(3×1×5)+2/(3×5×9)+2/(3×9×13)+……+2/(3×25×29)
=2/3×1/4(1-1/5+1/5-1/9+1/9-1/13+……+1/25-1/29)
=1/6×(1-1/29)
=1/6×28/29
=14/87
(9)4/(1×3×5)+4/(3×5×7)+4/(5×7×9)+……+4/(95×97×99)
=1/(1×3)-1/(3×5)+1/(3×5)-1/(5×7)+1/(5×7)-1/(7×9)+……+1/(95×97)-1/(97×99)
=1/(1×3)-1/(97×99)
=1/3-1/9603
=3200/9603
(10)1/(2×4×6)+1/(4×6×8)+1/(6×8×10)+……+1/(96×98×100)
=1/4×【1/(2×4)-1/(4×6)+1/(4×6)-1/(6×8)+1/(6×8)-1/(8×10)+……+1/(96×98)-1/(98×100)】
=1/4×【1/(2×4)-1/(98×100)】
=1/4×【1/8-1/9800】
=1/4×1224/9800
=153/4900
(11)1+(1/1+2)+(1/1+2+3)……+(1/1+2+3+4+5+6+7+8+9+10)
=1+2/(2×3)+2/(3×4)+……+2/(10×11)
=1+2×(1/2-1/3+1/3-1/4+……+1/10-1/11)
=1+2×(1/2-1/11)
=1+1-2/11
=1又9/11
(12)1/2+1/(2+4)+1/(2+4+6)+1/(2+4+6+8)+……+1/(2+4+6+8+……+98)
=1/2+1/6+1/12+1/20+……+1/(49×50)
=1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+……+1/49-1/50
=1-1/50
=49/50
(13)1/3+1/(3+6)+1/(3+6+9)+1/(3+6+9+12)+……+1/(3+6+9+12+……+99)
=2/3×(2+1/6+1/12+1/20+……+1/33×34)
=2/3×(2+1/2-1/3+1/3-1/4+1/4-1/5+……+1/33-1/34)
=2/3×(2+1/2-1/34)
=2/3×42/17
=28/17
其他的没时间了.‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍
 
 
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