如图,已知△ABC≌△ADE,且∠CAD=10°,∠B=∠D=25°,∠EAB=120°,求∠DFB和∠DGB

∠ACB=105°
∠FCA=180°-∠ACB=75°
∠CAD=10°
∠AFC=180°-∠FCA-∠CAD=95°
∠DFB=180°-∠AFC=85°
∠DGB=∠DFB-∠D=60°