简便计算：2x²-18/4-4x+x²÷【（x+3)·3-x/x²+6x+9】 要过程~

我想,你除号的后面一堆都是作分母吧.而且3-x应该有括号吧.按题意理解.最好加上括号.
=2(x^2-9)/(x^2-4x+4)/[(x+3)(3-x)/x^2+6x+9]
=2(x+3)(x-3)/(x-2)^2/[-(x+3)(x-3)/(x+3)^2]
=2/(x-2)^2/[-1/(x+3)^2]
=-2(x+3)^2/(x-2)^2