x=3,y=4,z=5,求以下表达式的值,怎么算 (x && y)==(x || z) (x>y)+(y!=z) ||

1.(x && y)==(x || z) -> (3 && 4)==(3 || 5) -> 1==1 ->1 2. !(x>y)+(y!=z) || (x+y)&&(y-z) -> !(3>4)+(4!=5) || (3+4)&&(4-5) -> !(3>4)+(4!=5) || 1 ->1 3.x++ -y+(++z) =3-4+6 =5