英语翻译ON THE NUMBER OF CONGRUENCE CLASSES OF PATHSZHICONG LIN

问题描述:

英语翻译
ON THE NUMBER OF CONGRUENCE CLASSES OF PATHS
ZHICONG LIN AND JIANG ZENG
Abstract.Let Pn denote the undirected path of length n − 1.The cardinality of the set of congruence classes induced by the graph homomorphisms from Pn onto Pk is determined.This settles an open problem of Michels and Knauer (Disc.Math.,309 (2009) 5352-5359).Our result is based on a new proven formula of the number of homomorphisms between paths.
Keywords:Graph,graph endomorphisms,graph homomorphisms,paths,lattice paths
1.Introduction
We use standard notations and terminology of graph theory in [3] or [6,Appendix].The graphs considered here are finite and undirected without multiple edges and loops.Given a graph G,we write V (G) for the vertex set and E(G) for the edge set.A homomorphism from a graph G to a graph H is a mapping f :V (G) → V (H) such that the images of adjacent vertices are adjacent.An endomorphism of a graph is a homomorphism from the graph to itself.Denote by Hom(G,H) the set of homomorphisms from G to H and by End(G) the set of endomorphisms of a graph G.For any finite set X we denote by |X| the cardinality of X.A path with n vertices is a graph whose vertices can be labeled v1,...,vn so that vi and vj are adjacent if and only if |i − j| = 1; let Pn denote such a graph with vi = i for 1 ≤ i ≤ n.Every endomorphism f on G induces a partition ρ of V (G),also called the congruence classes induced by f,with vertices in the same block if they have the same image.
Let C (Pn) denote the set of endomorphism-induced partitions of V (Pn),and let |ρ| denote the number of blocks in a partition ρ.For example,if f ∈ End(P4) is defined by f(1) = 3,f(2) = 2,f(3) = 1,f(4) = 2,then the induced partition ρ is {{1},{2,4},{3}} and |ρ| = 3.
The problem of counting the homomorphisms from G to H is difficult in general.How- ever,some algorithms and formulas for computing the number of homomorphisms of paths have been published recently (see [1,2,5]).In particular,Michels and Knauer [5] give an algorithm based on the epispectrum Epi(Pn) of a path Pn.They define Epi(Pn) = (l1(n),...,ln−1(n)),where
lk(n) = |{ρ ∈ C (Pn) :|ρ| = n − k + 1}|.(1.1)
Here a misprint in the definition of lk(n) in [5] is corrected.
In [5],based on the first values of lk(n),Michels and Knauer speculated the following conjecture.
1个回答 分类:英语 2014-12-09

问题解答:

我来补答
同余类的路径
ZHICONG林,江曾
摘要的数量.令Pn表示无向路径长度为n - 1.确定从的Pn到PK的图形同态诱导的同余类的集合的基数.这解决的一个公开问题的的米歇尔斯和克瑙尔(Disc.数学系,309(2009)5352-5359).我们的结果是基于一个新的行之有效的路径之间的数目同态.
关键词:图表,曲线图的自同态,图同态,路径,晶格路径
1.介绍
我们使用标准的符号和术语,图论[3]或[6,附录].这里考虑的是有限的图表和指导,没有多条边和循环.我们写的给定图G,V(G)的顶点集和边集E(G).从曲线图G甲同态到一个图H是一个映射f:V(G)→V(H),使得相邻顶点的图像相邻.自同态映射的曲线图,从图中本身是一个同态.记磡(G,H)的设置从G到H的同态和结束(G)图G的自同态的集合,我们表示对于任何有限集X | X |新路径的基数n个顶点vi和vj是一个图,它的顶点可以被标记为V1,...,VN,使相邻当且仅当| I - J | = 1;令Pn表示这样的图,用vi = I 1≤I ≤N.每一个自同态f的ĝ诱导
C(PN)表示集合的自同态引起的分区分区ρ为V(G),也被称为由f诱导的同余类,如果它们具有相同的图像的顶点在同一个街区.的V(Pn)的,并让|ρ|表示的块的数目在一个分区ρ.例如,如果f∈结束(P4),被定义为F(1)= 3,F(2)= 2,F(3)= 1,F(4)= 2,然后诱导分区ρ是{{1 },{2,4},{3}}和|ρ| = 3.
计数的同态从G到H的问题是难以普遍.然而,一些算法和公式计算同态的路径最近发表的(见[1,2,5]).特别是米歇尔斯和克瑙尔的[5]给出了一种算法的基础上的epispectrum长盈集团(PN)的路Pn.他们长盈集团(PN)=(L1(N),...,LN-1(N)),其中
LK(N)= | {ρ∈C(PN):|ρ| = - K + 1} |.(1.1)
LK(N)的定义[5]一个印刷错误被纠正.
[5]力劲(n)的,米歇尔斯和克瑙尔的第一个值的基础上,推测如下猜想.
 
 
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