若3的x次方=2,则log(2)9-log(3)8用x表示的代数式为

解
3^x=2
∴
log3(2)=x
∴
log2(3)=1/x
∴
log2(9)-log3(8)
=log2(3²)-log3(2³)
=2log2(3)-3log3(2)
=2/x-3x