若复数W与z在复平面内对应的点关于虚轴对称①求复数w②求复数w2/z+2的模

(1)m/(1-i)+1=m(1+i)/2+1=m/2+1+m/2i是纯虚数,则有m/2+1=0,m=-2
(2)w与z关于虚轴对称,则有w=-1+i
w^2=(-1+i)^2=1-1-2i=-2i
w^2/(z+2)=-2i/(1+i)=-2i(1-i)/2=-i-1
模=根号(1+1)=根号2