试求（2+1）（2的平方+1）（2的4次方十1）（2的8次方十1）（2的16次方十1）（2的32次方十1）十1．的值.

原式=(2-1)/(2-1)*(2+1)*(2^2+1)*(2^4+1)*(2^8+1)*(2^16+1)*(2^32+1)+1;
=(2-1)/1*(2+1)*(2^2+1)*(2^4+1)*(2^8+1)*(2^16+1)*(2^32+1)+1;
=(2^2-1)*(2^2+1)*(2^4+1)*(2^8+1)*(2^16+1)*(2^32+1)+1;
=(2^4-1)*(2^4+1)*(2^8+1)*(2^16+1)*(2^32+1)+1;
=(2^8-1)*(2^8+1)*(2^16+1)*(2^32+1)+1;
=(2^16-1)*(2^16+1)*(2^32+1)+1;
=(2^32-1)*(2^32+1)+1;
=(2^64-1)+1=2^64.