C语言循环求和SUM=1+(1/2)^2+(1/3)^3+(1/4)^4+(1/5)^5……一直算到精确度为0.0000

C语言循环求和
SUM=1+(1/2)^2+(1/3)^3+(1/4)^4+(1/5)^5……一直算到精确度为0.000001为止
/*SUM=1+(1/2)^2+(1/3)^3+(1/4)^4+(1/5)^5……*/
#include
#include
#define ACCURARY 0.000001
main()
{
\x09int i=1,j;
\x09double SUM=0,term=1;
\x09for(i=1;term>=ACCURARY;i++)
\x09{
\x09\x09for(j=1;j