已知x=-2是关于x的一元二次方程4a²x²+4ax+b-8=0的一个根

跟老师要答案得了.
4a^2(-2)^2 + 4a(-2) + b - 8 = 0,
b = -8,
16a^2 - 8a - 16 = 0,
2a^2 - a - 2 = 0,
1^2 + 4*2*2 = 17.
a = [1 - (17)^(1/2)]/4 或 a = [1 + (17)^(1/2)]/4
a是实数时,由
4a^2(-2)^2 + 4a(-2) + b - 8 = 0,
b = 8 - 16a^2 + 8a = 8[1 + a - 2a^2]
= 16[1/2 + a/2 - a^2]
= 16[3/4 - 1/4 + a/2 - a^2]
= 3/4 - 16(a - 1/2)^2
>= 3/4