【数学分式计算,(a²-4)分之2a-(a-2)分之1 (x-3)分之1-(x+3)分之1

问题描述:

【数学分式计算,(a²-4)分之2a-(a-2)分之1 (x-3)分之1-(x+3)分之1
(a²-4)分之2a-(a-2)分之1
(x-3)分之1-(x+3)分之1
(a²-4a+4)分之(a-1)÷(a²-4)分之(a²-1)
【(x-2)分之3x-(x+2)分之x】×x分之(x²-4)
1个回答 分类:数学 2014-10-07

问题解答:

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(a²-4)分之2a-(a-2)分之1
=2a/(a+2)(a-2)-(a+2)/(a+2)(a-2)
=(2a-a-2)/(a+2)(a-2)
=(a-2)/(a+2)(a-2)
=1/(a+2)
(x-3)分之1-(x+3)分之1
=(x+3)/(x+3)(x-3)-(x-3)/(x+3)(x-3)
=(x+3-x+3)/(x+3)(x-3)
=6/(x²-9)
(a²-4a+4)分之(a-1)÷(a²-4)分之(a²-1)
=(a-1)/(a-2)²×(a+2)(a-2)/(a+1)(a-1)
=(a+2)/(a-2)(a+1)
=(a+2)/(a²-a-2)
【(x-2)分之3x-(x+2)分之x】×x分之(x²-4)
=[3x/(x-2)-x/(x+2)]×(x+2)(x-2)/x
=3(x+2)-(x-2)
=3x+6-x+2
=2x+8
 
 
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