已知:x=五又七分之四,y=四又七分之三,求代数式[-三又二分之一(x+y)]^3×(x-y)×[-2(x-y)(x+y

问题描述:

已知:x=五又七分之四,y=四又七分之三,求代数式[-三又二分之一(x+y)]^3×(x-y)×[-2(x-y)(x+y)]^2的值
1个回答 分类:数学 2014-10-17

问题解答:

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x=5+4/7,y=4+3/7
x+y=9+7/7=10
x-y=1+1/7=8/7
[(-3-1/2)(x+y)]^3 * (x-y) * [-2(x-y)(x+y)]^2
=-(7/2)^3 * (-2)^2 * (x+y)^3 * (x-y) * (x-y)^2 * (x+y)^2
=-7^3 /2 * (x+y)^5 * (x-y)^3
=-7^3 /2 * 10^5 * (8/7)^3
=-7^3 /2 * 10^5 * 8^3 / 7^3
=-256*10^5
=-25600000
 
 
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