99又3分之1×100又3分之2= 2(3+1)(3²+1)·∧·(3的32次+1)+1= 9(3分之1x+2

问题描述:

99又3分之1×100又3分之2= 2(3+1)(3²+1)·∧·(3的32次+1)+1= 9(3分之1x+2)(x-6)-(-2x)²=
1个回答 分类:数学 2014-10-23

问题解答:

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99又3分之1×100又3分之2=(100-2/3)(100+2/3)=10000-4/9=9999又5/9
2(3+1)(3²+1)·∧·(3的32次+1)+1
=2*(1/2)(3-1)(3+1)(3^2+1)*.*(3^32+1)+1
=(3^2-1)(3^2+1)*.*(3^32+1)+1
=(3^64-1)+1
=3^64
9(3分之1x+2)(x-6)-(-2x)²
=(3x+18)(x-6)-4x^2
=3(x+6)(x-6)-4x^2
=3x^2-108-4x^2
=-x^2-108
 
 
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