先化简,在求值：(x+根号xy)/(y+根号xy)+((根号xy)-y)/(x-根号xy),其中x=根号3+1,y=根号

(x+根号xy)/(y+根号xy)+((根号xy)-y)/(x-根号xy),
=√x(√x+√y)/√y(√x+√y)+√y(√x-√y)/√x(√x-√y)
=√x/√y+√y/√x=(x+y)/√xy
x=√3+1 y=√3-1 ∴x+y=2√3 xy=2
∴(x+y)/√xy=2√3/2=√3