d/dx定积分(0~x^2) (1+t^2)^(1/2）dt d/dx定积分（0~x^2）（x^1/2)cost^2dt

1、=2x(1+x^4)^(1/2）
2、=d/dx（x^1/2)*∫ （0~x^2）cost^2dt
=(1/2)x^(-1/2)*∫ （0~x^2）cost^2dt+(x^(1/2))*cos(x^4) *2x
=(1/2)x^(-1/2)*∫ （0~x^2）cost^2dt+2(x^(3/2))*cos(x^4)