x^2+y^2=7,xy=-2,求多项式5x^2-3xy-4y^2-11xy-7x^2+2y^2的值

问题描述:

x^2+y^2=7,xy=-2,求多项式5x^2-3xy-4y^2-11xy-7x^2+2y^2的值
1个回答 分类:综合 2014-11-16

问题解答:

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5x^2-3xy-4y^2-11xy-7x^2+2y^2
=-2x²-2y²-14xy
=-2(x²+y²)-14xy
=-2×7-14×(-2)
=-14+28
=14
 
 
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